(a³b–8c—8) ²
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(a²b–5c–6)³![]()
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(a²b–5c–6)³
[tex]\frac{{({a}^{3} {b}^{ - 8} {c}^{ - 8})}^{2}}{{({a}^{2} {b}^{ - 5} {c}^{ - 6})}^{3}} = \frac{({a}^{3 \times 2} {b}^{( - 8) \times 2} {c}^{( - 8) \times 2})}{({a}^{2 \times 3} {b}^{( - 5) \times 3} {c}^{( - 6) \times 3})} = \frac{({a}^{6} {b}^{ - 16} {c}^{ - 16})}{({a}^{6} {b}^{ - 15} {c}^{ - 18})} [/tex]
[tex]= {a}^{6 - 6} {b}^{( - 16) - ( - 15)} {c}^{( - 16) - ( - 18)} [/tex]
[tex]= {a}^{0} {b}^{( - 16) + 15} {c}^{( - 16) + 18} = 1 \times {b}^{ - 1} {c}^{2} = \frac{{c}^{2}}{b} [/tex]
[answer.2.content]
